r^2+22r+60=0

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Solution for r^2+22r+60=0 equation:


Simplifying
r2 + 22r + 60 = 0

Reorder the terms:
60 + 22r + r2 = 0

Solving
60 + 22r + r2 = 0

Solving for variable 'r'.

Begin completing the square.

Move the constant term to the right:

Add '-60' to each side of the equation.
60 + 22r + -60 + r2 = 0 + -60

Reorder the terms:
60 + -60 + 22r + r2 = 0 + -60

Combine like terms: 60 + -60 = 0
0 + 22r + r2 = 0 + -60
22r + r2 = 0 + -60

Combine like terms: 0 + -60 = -60
22r + r2 = -60

The r term is 22r.  Take half its coefficient (11).
Square it (121) and add it to both sides.

Add '121' to each side of the equation.
22r + 121 + r2 = -60 + 121

Reorder the terms:
121 + 22r + r2 = -60 + 121

Combine like terms: -60 + 121 = 61
121 + 22r + r2 = 61

Factor a perfect square on the left side:
(r + 11)(r + 11) = 61

Calculate the square root of the right side: 7.810249676

Break this problem into two subproblems by setting 
(r + 11) equal to 7.810249676 and -7.810249676.

Subproblem 1

r + 11 = 7.810249676 Simplifying r + 11 = 7.810249676 Reorder the terms: 11 + r = 7.810249676 Solving 11 + r = 7.810249676 Solving for variable 'r'. Move all terms containing r to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + r = 7.810249676 + -11 Combine like terms: 11 + -11 = 0 0 + r = 7.810249676 + -11 r = 7.810249676 + -11 Combine like terms: 7.810249676 + -11 = -3.189750324 r = -3.189750324 Simplifying r = -3.189750324

Subproblem 2

r + 11 = -7.810249676 Simplifying r + 11 = -7.810249676 Reorder the terms: 11 + r = -7.810249676 Solving 11 + r = -7.810249676 Solving for variable 'r'. Move all terms containing r to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + r = -7.810249676 + -11 Combine like terms: 11 + -11 = 0 0 + r = -7.810249676 + -11 r = -7.810249676 + -11 Combine like terms: -7.810249676 + -11 = -18.810249676 r = -18.810249676 Simplifying r = -18.810249676

Solution

The solution to the problem is based on the solutions from the subproblems. r = {-3.189750324, -18.810249676}

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